Comic #3831: a-proof

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Description

Here is the transcription of the text from the comic:

PROOF:

( e^{i \cdot P_i} = -1 )

And,
( P_i = P \cdot i )

So,
( e^{i \cdot P_i} = e^{P \cdot i \cdot i} = e^{-P} )

So,
( e^{-P} = -1 )

Squaring both sides,
( e^{-2P} = 1 )

Which leaves
( P = 0 )

Thus,
( P = NP )

QED

This includes all the mathematical expressions and their arrangements as seen in the comic.